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X^2+X^2=90000
We move all terms to the left:
X^2+X^2-(90000)=0
We add all the numbers together, and all the variables
2X^2-90000=0
a = 2; b = 0; c = -90000;
Δ = b2-4ac
Δ = 02-4·2·(-90000)
Δ = 720000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{720000}=\sqrt{360000*2}=\sqrt{360000}*\sqrt{2}=600\sqrt{2}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-600\sqrt{2}}{2*2}=\frac{0-600\sqrt{2}}{4} =-\frac{600\sqrt{2}}{4} =-150\sqrt{2} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+600\sqrt{2}}{2*2}=\frac{0+600\sqrt{2}}{4} =\frac{600\sqrt{2}}{4} =150\sqrt{2} $
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